English
There is a natural equivalence between BotHom α β and TopHom αᵒᵈ βᵒᵈ.
Русский
Существует естественное эквивалентное соответствие между BotHom α β и TopHom αᵒᵈ βᵒᵈ.
LaTeX
$$$\mathrm{BotHom}(\alpha,\beta) \simeq \mathrm{TopHom}(\alpha^{\mathrm{op}},\beta^{\mathrm{op}})$$$
Lean4
/-- Reinterpret a bot homomorphism as a top homomorphism between the dual lattices. -/
@[simps]
protected def dual : BotHom α β ≃ TopHom αᵒᵈ βᵒᵈ
where
toFun f := ⟨f, f.map_bot'⟩
invFun f := ⟨f, f.map_top'⟩