English
For m ∈ Nat, i, j ∈ Fin n, map (natAddEmb m) on Icc i j equals Icc (natAdd m i) (natAdd m j).
Русский
Для m ∈ Nat, i, j ∈ Fin n отображение natAddEmb m на Icc i j даёт Icc (natAdd m i) (natAdd m j).
LaTeX
$$$$(\\mathrm{Icc}\\ i\\ j).\\operatorname{map}(\\mathrm{natAddEmb}\\ m) = \\mathrm{Icc}(\\mathrm{natAdd}\\ m\,i, \\mathrm{natAdd}\\ m\,j)$$$$
Lean4
@[simp]
theorem map_natAddEmb_Icc (m) (i j : Fin n) : (Icc i j).map (natAddEmb m) = Icc (natAdd m i) (natAdd m j) := by
simp [← coe_inj]