English
For m ∈ Nat, i, j ∈ Fin n, map (natAddEmb m) on Ico i j equals Ico (natAdd m i) (natAdd m j).
Русский
Для m ∈ Nat, i, j ∈ Fin n отображение natAddEmb m на Ico i j даёт Ico (natAdd m i) (natAdd m j).
LaTeX
$$$$(\\mathrm{Ico}\\ i\\ j).\\operatorname{map}(\\mathrm{natAddEmb}\\ m) = \\mathrm{Ico}(\\mathrm{natAdd}\\ m\,i, \\mathrm{natAdd}\\ m\,j)$$$$
Lean4
@[simp]
theorem map_natAddEmb_Ico (m) (i j : Fin n) : (Ico i j).map (natAddEmb m) = Ico (natAdd m i) (natAdd m j) := by
simp [← coe_inj]