English
The preimage under the order dual map commutes with latticeClosure.
Русский
Предобраз под отображением двойственной порядка сохраняет latticeClosure.
LaTeX
$$$\operatorname{ofDual}^{-1} \; \mathrm{latticeClosure}(s) = \mathrm{latticeClosure}(\operatorname{ofDual}^{-1} s)$$$
Lean4
theorem ofDual_preimage_latticeClosure (s : Set α) : ofDual ⁻¹' latticeClosure s = latticeClosure (ofDual ⁻¹' s) :=
by
change ClosureOperator.ofCompletePred _ _ _ = ClosureOperator.ofCompletePred _ _ _
congr 2
ext
exact ⟨fun h => ⟨h.2, h.1⟩, fun h => ⟨h.2, h.1⟩⟩