English
There is a formula for (leftHomologyMap φ).op expressed by S2.rightHomologyOpIso.inv, rightHomologyMap (opMap φ), and S1.rightHomologyOpIso.hom.
Русский
Существует формула для (leftHomologyMap φ).op через S2.rightHomologyOpIso.inv, rightHomologyMap (opMap φ) и S1.rightHomologyOpIso.hom.
LaTeX
$$(leftHomologyMap φ).op = S2.rightHomologyOpIso.inv ≫ rightHomologyMap (opMap φ) ≫ S1.rightHomologyOpIso.hom$$
Lean4
theorem leftHomologyMap_op (φ : S₁ ⟶ S₂) [S₁.HasLeftHomology] [S₂.HasLeftHomology] :
(leftHomologyMap φ).op = S₂.rightHomologyOpIso.inv ≫ rightHomologyMap (opMap φ) ≫ S₁.rightHomologyOpIso.hom :=
by
dsimp [rightHomologyOpIso, RightHomologyData.rightHomologyIso, rightHomologyMap, leftHomologyMap]
simp only [← rightHomologyMap'_comp, comp_id, id_comp, leftHomologyMap'_op]