rightHomologyι_comp_fromOpcycles

English

The inverse of opcyclesIso composed with descOpcycles equals descQ: h.opcyclesIso.inv ≫ S.descOpcycles k hk = h.descQ k hk.

Русский

Обратное к opcyclesIso, композиция с descOpcycles даёт descQ: h.opcyclesIso.inv ≫ S.descOpcycles k hk = h.descQ k hk.

LaTeX

$$$h.opcyclesIso^{-1} \\circ S.descOpcycles k hk = h.descQ k hk$$$

Lean4

@[reassoc (attr := simp)]
theorem rightHomologyι_comp_fromOpcycles : S.rightHomologyι ≫ S.fromOpcycles = 0 :=
  S.rightHomologyι_descOpcycles_π_eq_zero_of_boundary S.g (𝟙 _) (by rw [comp_id])

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