English
If f=g, then the deterministic kernels coincide after transporting the measurability: deterministic f hf = deterministic g (h ▸ hf).
Русский
Если f=g,Deterministic ядра совпадают после переноса измеримости.
LaTeX
$$$\deterministic f hf = \deterministic g (h \;▸\; hf)$, если $h: f=g$$$
Lean4
/-- Because of the measurability field in `Kernel.deterministic`, `rw [h]` will not rewrite
`deterministic f hf` to `deterministic g ⋯`. Instead one can do `rw [deterministic_congr h]`. -/
theorem deterministic_congr {f g : α → β} {hf : Measurable f} (h : f = g) :
deterministic f hf = deterministic g (h ▸ hf) := by grind