English
Let κ: Kernel α β and η i: ι → Kernel β γ with ι countable. Then (Kernel.sum η) ∘ₖ κ = Kernel.sum (i ↦ (η i) ∘ₖ κ).
Русский
Пусть κ: α → β и η_i: β → γ для i в ι, где ι счётно. Тогда (Kernel.sum η) ∘ₖ κ = Kernel.sum (i ↦ (η i) ∘ₖ κ).
LaTeX
$$$ (Kernel.sum \eta) \circ_K \kappa = Kernel.sum (\lambda i. (\eta i) \circ_K \kappa) $$$
Lean4
theorem comp_sum_left {ι : Type*} [Countable ι] (κ : Kernel α β) (η : ι → Kernel β γ) :
(Kernel.sum η) ∘ₖ κ = Kernel.sum (fun i ↦ (η i) ∘ₖ κ) :=
by
ext _ _ hs
simp_rw [sum_apply, comp_apply' _ _ _ hs, sum_apply, Measure.sum_apply _ hs, comp_apply' _ _ _ hs]
rw [lintegral_tsum]
exact fun _ ↦ (Kernel.measurable_coe _ hs).aemeasurable