English
If f is strongly measurable and integrable, then almost everywhere on μ.trim hm, condExp and the integral over condExpKernelμ m reproduce f almost everywhere.
Русский
Если f сильно измерима и интегрируема, то почти всюду на μ.trim hm condExp и интеграл по condExpKernel μ m восстанавливают f почти наверняка.
LaTeX
$$$\\text{StronglyMeasurable}(f) \\Rightarrow \\text{ae}_{μ.trim hm}(f)\\Rightarrow \\text{ae}_{μ.trim hm}(f = \\int f d condExpKernel)$$$
Lean4
/-- Auxiliary lemma for `condExp_ae_eq_trim_integral_condExpKernel`. -/
theorem condExp_ae_eq_trim_integral_condExpKernel_of_stronglyMeasurable [NormedAddCommGroup F] {f : Ω → F}
[NormedSpace ℝ F] [CompleteSpace F] (hm : m ≤ mΩ) (hf : StronglyMeasurable f) (hf_int : Integrable f μ) :
μ[f|m] =ᵐ[μ.trim hm] fun ω ↦ ∫ y, f y ∂condExpKernel μ m ω :=
by
refine StronglyMeasurable.ae_eq_trim_of_stronglyMeasurable hm ?_ ?_ ?_
· exact stronglyMeasurable_condExp
· exact hf.integral_condExpKernel
· exact condExp_ae_eq_integral_condExpKernel hm hf_int