English
Given κ, η, ξ and f with κ = η.withDensity f + ξ, and a such that ξ a ⟂ η a, the value of ξ a on a set equals the singularPart of κ a with respect to η a on that set.
Русский
Пусть κ = η.withDensity f + ξ и ξ a ⟂ η a; тогда ξ a на заданном множестве равно сингулярной части κ a относительно η a на этом множестве.
LaTeX
$$ξ a = (κ a).singularPart(η a)$$
Lean4
theorem eq_singularPart_measure (h : κ = η.withDensity f + ξ) (hf : Measurable (Function.uncurry f)) (a : α)
(hξ : ξ a ⟂ₘ η a) : ξ a = (κ a).singularPart (η a) :=
by
have : κ a = ξ a + (η a).withDensity (f a) := by rw [h, coe_add, Pi.add_apply, η.withDensity_apply hf, add_comm]
exact (κ a).eq_singularPart (hf.comp measurable_prodMk_left) hξ this