English
Repeated statement: under IsKolmogorovProcess, if edist s t = 0 then edist(X_s ω, X_t ω) = 0 a.e.
Русский
Повторно: при IsKolmogorovProcess, если edist(s,t)=0, то edist(X_s ω, X_t ω) = 0 почти surely.
LaTeX
$$$\\forall s,t,\\ edist(s,t)=0 \\Rightarrow \\ edist(X_s, X_t)=0\\; \\text{a.e.}$$$
Lean4
theorem edist_eq_zero (hX : IsAEKolmogorovProcess X P p q M) {s t : T} (h : edist s t = 0) :
∀ᵐ ω ∂P, edist (X s ω) (X t ω) = 0 :=
by
suffices ∀ᵐ ω ∂P, edist (X s ω) (X t ω) ^ p = 0
by
filter_upwards [this] with ω hω
simpa [hX.p_pos, not_lt_of_gt hX.p_pos] using hω
refine (lintegral_eq_zero_iff' (hX.aemeasurable_edist.pow_const p)).mp ?_
refine le_antisymm ?_ zero_le'
calc
∫⁻ ω, edist (X s ω) (X t ω) ^ p ∂P
_ ≤ M * edist s t ^ q := (hX.kolmogorovCondition s t)
_ = 0 := by simp [h, hX.q_pos]