English
If hτ ≤ hπ as stopping-time spaces, then hτ.measurableSpace ≤ hπ.measurableSpace.
Русский
Если пространства измеримости для двух остановочных времен удовлетворяют неравенству, то первое пространство подмножество второго.
LaTeX
$$$h_{\tau}.\mathrm{measurableSpace} \le h_{\pi}.\mathrm{measurableSpace}$$$
Lean4
theorem measurableSpace_mono (hτ : IsStoppingTime f τ) (hπ : IsStoppingTime f π) (hle : τ ≤ π) :
hτ.measurableSpace ≤ hπ.measurableSpace := by
intro s hs i
rw [(_ : s ∩ {ω | π ω ≤ i} = s ∩ {ω | τ ω ≤ i} ∩ {ω | π ω ≤ i})]
· exact (hs i).inter (hπ i)
· ext
simp only [Set.mem_inter_iff, iff_self_and, and_congr_left_iff, Set.mem_setOf_eq]
intro hle' _
exact le_trans (hle _) hle'