English
The identity on the source G composes with φ and ψ as expected: mapShortComplexH2(id_G)(φ ≫ ψ) = mapShortComplexH2(id_G) φ ≫ mapShortComplexH2(id_G) ψ.
Русский
Единичное отображение на G компонуется с φ и ψ как положено: mapShortComplexH2(id_G)(φ ≫ ψ) = mapShortComplexH2(id_G) φ ∘ mapShortComplexH2(id_G) ψ.
LaTeX
$$$ mapShortComplexH2(\mathrm{id}_G)(\varphi \;\mathrm{≫}\; \psi) = mapShortComplexH2(\mathrm{id}_G)\varphi \;\mathrm{≫}\; mapShortComplexH2(\mathrm{id}_G)\psi $$$
Lean4
theorem mapShortComplexH2_id_comp {A B C : Rep k G} (φ : A ⟶ B) (ψ : B ⟶ C) :
mapShortComplexH2 (MonoidHom.id G) (φ ≫ ψ) =
mapShortComplexH2 (MonoidHom.id G) φ ≫ mapShortComplexH2 (MonoidHom.id G) ψ :=
mapShortComplexH2_comp (MonoidHom.id G) (MonoidHom.id G) _ _