English
If R is Noetherian, then for any ideal I, the quotient R/I is Noetherian.
Русский
Если R же Неттерское кольцо, то R/I тоже Неттерское для любого идеала I.
LaTeX
$$$$\text{IsNoetherianRing}(R/I).$$$$
Lean4
theorem index_pow_le (s : Finset R) (hs : Ideal.span s = I) [Finite (R ⧸ I)] (n) :
(I ^ n).toAddSubgroup.index ≤ I.toAddSubgroup.index ^ ∑ i ∈ Finset.range n, s.card ^ i :=
by
have := Ideal.finite_quotient_pow ⟨s, hs⟩
induction n with
| zero => simp
| succ n IH =>
refine (Submodule.index_smul_le (I ^ n) s hs).trans ?_
refine (Nat.mul_le_mul (Nat.pow_le_pow_left IH _) le_rfl).trans ?_
rw [← pow_mul, ← pow_succ, geom_sum_succ, mul_comm]