English
For a ring homomorphism f: A → B, the lift map kerLift: A/(ker f) → B is linear over the base ring; in particular, it respects scalars: kerLift(r·x) = r·kerLift(x) for r in the base ring and x in A/(ker f).
Русский
Пусть f: A → B — кольцевой гомоморфизм. Лифт-отображение kerLift: A/(ker f) → B является линейным относительно основания: kerLift(r·x) = r·kerLift(x).
LaTeX
$$$\; kerLift(f)(r \cdot x) = r \cdot kerLift(f)(x)$$$
Lean4
theorem map_smul (f : A →ₐ[R₁] B) (r : R₁) (x : A ⧸ (RingHom.ker f)) : f.kerLift (r • x) = r • f.kerLift x :=
by
obtain ⟨a, rfl⟩ := Quotient.mkₐ_surjective R₁ _ x
exact _root_.map_smul f _ _