English
In a commutative ring, the span of {x + y z, y} equals the span of {x, y} for any z.
Русский
В коммутативном кольце порождение {x + y z, y} равно порождению {x, y} для любого z.
LaTeX
$$$$ \operatorname{span}(\{ x + y z, y \}) = \operatorname{span}(\{ x, y \}) $$$$
Lean4
@[simp]
theorem span_pair_add_mul_left {R : Type u} [CommRing R] {x y : R} (z : R) :
(span {x + y * z, y} : Ideal R) = span { x, y } := by
ext
rw [mem_span_pair, mem_span_pair]
exact
⟨fun ⟨a, b, h⟩ =>
⟨a, b + a * z, by
rw [← h]
ring1⟩,
fun ⟨a, b, h⟩ =>
⟨a, b - a * z, by
rw [← h]
ring1⟩⟩