English
The Frobenius and pthRoot maps compose to identity on Ring.Perfection: Frobenius_pthRoot = id.
Русский
Фробениус и pthRoot образуют тождественность: Frobenius_pthRoot = id.
LaTeX
$$$(\\mathrm{frobenius}_{p}) \\circ (\\mathrm{pthRoot} \\; R \\; p) = \\mathrm{id}_{\\mathrm{Ring.Perfection}(R,p)}$$$
Lean4
theorem frobenius_pthRoot : (frobenius _ p).comp (pthRoot R p) = RingHom.id _ :=
RingHom.ext fun x =>
ext fun n => by
rw [RingHom.comp_apply, RingHom.id_apply, RingHom.map_frobenius, coeff_pthRoot, ←
@RingHom.map_frobenius (Ring.Perfection R p) _ R, coeff_frobenius]