English
For any ring hom f:S→+*T, the two-variable evaluation relation holds: (ascPochhammer T n).eval t = (ascPochhammer S n).eval₂ f t.
Русский
Для любого гомоморфа f: S→+*T верно равенство: (ascPochhammer T n).eval t = (ascPochhammer S n).eval₂ f t.
LaTeX
$$$ (ascPochhammer T\\, n).\\mathrm{eval}\\ t = (ascPochhammer S\\, n).\\mathrm{eval_2}\\ f\\ t $$$
Lean4
theorem ascPochhammer_eval₂ (f : S →+* T) (n : ℕ) (t : T) :
(ascPochhammer T n).eval t = (ascPochhammer S n).eval₂ f t :=
by
rw [← ascPochhammer_map f]
exact eval_map f t