English
Given substitutions ha and hb, the composed substitution map ((substAlgHom hb).restrictScalars R).comp (substAlgHom ha) equals substAlgHom (ha.comp hb).
Русский
При подстановках ha и hb композиция ((substAlgHom hb).restrictScalars R).comp (substAlgHom ha) равна substAlgHom (ha.comp hb).
LaTeX
$$$((\\text{substAlgHom hb}).restrictScalars R) .\\,\\text{comp} \\; (\\text{substAlgHom ha}) = \\text{substAlgHom}(ha.comp hb)$$$
Lean4
theorem substAlgHom_comp_substAlgHom (ha : HasSubst a) (hb : HasSubst b) :
((substAlgHom hb).restrictScalars R).comp (substAlgHom ha) = substAlgHom (ha.comp hb) :=
MvPowerSeries.substAlgHom_comp_substAlgHom _ _