English
For any f and a ∈ N, trunc n ((trunc n f)^a) = trunc n (f^a).
Русский
Для любого f и a ∈ N: trunc n ((trunc n f)^a) = trunc n (f^a).
LaTeX
$$$\\forall f:\\; \\mathbb{R}\\langle\\langle X \\rangle\\rangle, \\forall a \\in \\mathbb{N}, \\; \\operatorname{trunc} n ((\\operatorname{trunc} n f)^a) = \\operatorname{trunc} n (f^a)$$$
Lean4
@[simp]
theorem trunc_trunc_pow (f : R⟦X⟧) (n a : ℕ) : trunc n ((trunc n f : R⟦X⟧) ^ a) = trunc n (f ^ a) := by
induction a with
| zero => rw [pow_zero, pow_zero]
| succ a ih =>
rw [_root_.pow_succ', _root_.pow_succ', trunc_trunc_mul, ← trunc_trunc_mul_trunc, ih, trunc_trunc_mul_trunc]