English
If f: A →ₐ[R] B is surjective and A is unramified over R, then B is unramified over R.
Русский
Если алгебра-гомоморфизм f: A → B над R сюръективен и A неразветвлена над R, то B тоже неразвлена над R.
LaTeX
$$$[\text{Surjective } f] \land [\text{Unramified } R \; A] \Rightarrow [\text{Unramified } R \; B]$$$
Lean4
/-- This holds in general for epimorphisms. -/
theorem of_surjective [FormallyUnramified R A] (f : A →ₐ[R] B) (H : Function.Surjective f) : FormallyUnramified R B :=
by
rw [iff_comp_injective]
intro Q _ _ I hI f₁ f₂ e
ext x
obtain ⟨x, rfl⟩ := H x
rw [← AlgHom.comp_apply, ← AlgHom.comp_apply]
congr 1
apply FormallyUnramified.comp_injective I hI
ext x; exact DFunLike.congr_fun e (f x)