English
For all x,y, the birthday of x+y is at most the natural sum of their birthdays.
Русский
Для любых x,y день рождения x+y не превосходит естественной суммы их дней рождения.
LaTeX
$$$\operatorname{birthday}(x + y) \le \operatorname{birthday}(x) ⊞ \operatorname{birthday}(y)$$$
Lean4
theorem birthday_add_le (x y : Game) : (x + y).birthday ≤ x.birthday ♯ y.birthday :=
by
let ⟨a, ha₁, ha₂⟩ := birthday_eq_pGameBirthday x
let ⟨b, hb₁, hb₂⟩ := birthday_eq_pGameBirthday y
rw [← ha₂, ← hb₂, ← ha₁, ← hb₁, ← PGame.birthday_add]
exact birthday_quot_le_pGameBirthday _