English
For any a and l, SizeOf of the pair (b, a) is smaller than SizeOf of cons'(a, l).
Русский
Для любого a и l, размер пары (b, a) меньше размера конструируемого списка cons'(a, l).
LaTeX
$$$\\operatorname{SizeOf.sizeOf}(\\langle b, a \\rangle) < \\operatorname{SizeOf.sizeOf}(\\text{Lists'.cons'}'(a,l))$$$
Lean4
theorem lt_sizeof_cons' {b} (a : Lists' α b) (l) :
SizeOf.sizeOf (⟨b, a⟩ : Lists α) < SizeOf.sizeOf (Lists'.cons' a l) :=
by
simp only [Sigma.mk.sizeOf_spec, Lists'.cons'.sizeOf_spec, lt_add_iff_pos_right]
apply sizeof_pos