English
For any ι with a well-order r, brange of bfamOfFamily' equals range f.
Русский
Для любого ι с хорошим порядком r brange bfamilyOfFamily' равен range f.
LaTeX
$$$\mathrm{brange}(o,\mathrm{bfamilyOfFamily'}(r,f)) = \mathrm{range} f$$$
Lean4
@[simp]
theorem brange_bfamilyOfFamily' {ι : Type u} (r : ι → ι → Prop) [IsWellOrder ι r] (f : ι → α) :
brange _ (bfamilyOfFamily' r f) = range f :=
by
refine Set.ext fun a => ⟨?_, ?_⟩
· rintro ⟨i, hi, rfl⟩
apply mem_range_self
· rintro ⟨b, rfl⟩
exact ⟨_, _, bfamilyOfFamily'_typein _ _ _⟩