English
The fast growing function at 1 reduces to a simple expression: fastGrowing 1 = fun n => 2 * n.
Русский
FastGrowing при 1 даёт простую формулу: fastGrowing 1 = fun n => 2 * n.
LaTeX
$$$\\operatorname{fastGrowing}(1) = \\lambda n. 2n$$$
Lean4
@[simp]
theorem fastGrowing_one : fastGrowing 1 = fun n => 2 * n :=
by
rw [@fastGrowing_succ 1 0 rfl]; funext i; rw [two_mul, fastGrowing_zero]
suffices ∀ a b, Nat.succ^[a] b = b + a from this _ _
intro a b; induction a <;> simp [*, Function.iterate_succ', Nat.add_assoc, -Function.iterate_succ]