English
If g is injective, then HasProd f a with respect to the map L.map g is equivalent to HasProd (f ∘ g) a with respect to L.
Русский
Если g внедримо, то HasProd f a по L.map g эквивалентно HasProd (f ∘ g) a по L.
LaTeX
$$$ HasProd f a (L.map ⟨g, hg⟩) \leftrightarrow HasProd (f \circ g) a L $$$
Lean4
@[inherit_doc tsum, term_parser 1000]
public meta def «term∑'[_]_,_» : Lean.ParserDescr✝ :=
ParserDescr.node✝ `«term∑'[_]_,_» 1022
(ParserDescr.binary✝ `andthen
(ParserDescr.binary✝ `andthen
(ParserDescr.binary✝ `andthen
(ParserDescr.binary✝ `andthen
(ParserDescr.binary✝ `andthen (ParserDescr.symbol✝ "∑'[") (ParserDescr.cat✝ `term 0))
(ParserDescr.symbol✝ "]"))
Batteries.ExtendedBinder.extBinders)
(ParserDescr.symbol✝ ", "))
(ParserDescr.cat✝ `term 67))