English
If f: X → Y is continuous and hs respects equivalence classes, then Quotient.liftOn' x f hs is continuous on Quotient s → Y.
Русский
Пусть f: X → Y непрерывно и hs согласован с эквивалентностями; тогда Quotient.liftOn' x f hs непрерывно на Quotient s → Y.
LaTeX
$$$$ \mathrm{Continuous}(\operatorname{Quotient.liftOn'}(x, f, hs)) $$$$
Lean4
theorem quotient_liftOn' {f : X → Y} (h : Continuous f) (hs : ∀ a b, s a b → f a = f b) :
Continuous (fun x => Quotient.liftOn' x f hs : Quotient s → Y) :=
h.quotient_lift hs