English
If s is stable under specialization and f is continuous, then the preimage f^{-1}(s) is stable under specialization.
Русский
Если s стабильно по специализации и f непрерывна, то прообраз f^{-1}(s) стабилен по специализации.
LaTeX
$$$StableUnderSpecialization(s) \Rightarrow (\text{Continuous}(f) \Rightarrow StableUnderSpecialization(f^{-1}(s)))$$$
Lean4
theorem preimage {s : Set Y} (hs : StableUnderSpecialization s) (hf : Continuous f) :
StableUnderSpecialization (f ⁻¹' s) :=
IsLowerSet.preimage hs hf.specialization_monotone