English
Replacing a set by its closure does not change the Hausdorff distance: hausdorffDist(s, closure(s)) = hausdorffDist(s, s).
Русский
Замена множества его замыканием не меняет расстояние Хаусдорфа: hausdorffDist(s, closure(s)) = hausdorffDist(s, s).
LaTeX
$$$\operatorname{hausdorffDist}(\overline{s}, s) = \operatorname{hausdorffDist}(s,s).$$$
Lean4
/-- The Hausdorff distance satisfies the triangle inequality. -/
theorem hausdorffDist_triangle' (fin : hausdorffEdist t u ≠ ⊤) :
hausdorffDist s u ≤ hausdorffDist s t + hausdorffDist t u :=
by
rw [hausdorffEdist_comm] at fin
have I : hausdorffDist u s ≤ hausdorffDist u t + hausdorffDist t s := hausdorffDist_triangle fin
simpa [add_comm, hausdorffDist_comm] using I