English
In any T1 space, for distinct x,y, the neighborhood filter of x restricted to the complement of {x} is contained in the neighborhood filter restricted to the complement of {y}.
Русский
Для любого T1-пространства, при x ≠ y, фильтр окрестностей x внутри дополнения к {x} вложен в фильтр окрестностей x внутри дополнения к {y}.
LaTeX
$$$\\forall X [\\mathcal{T}_1(X)], \\forall x,y\\in X, x\\neq y \\Rightarrow nhdsWithin(x, X\\setminus\\{x\\}) \\le nhdsWithin(x, X\\setminus\\{y\\}).$$$
Lean4
theorem nhdsWithin_compl_singleton_le [T1Space X] (x y : X) : 𝓝[{ x }ᶜ] x ≤ 𝓝[{ y }ᶜ] x :=
by
rcases eq_or_ne x y with rfl | hy
· exact Eq.le rfl
· rw [Ne.nhdsWithin_compl_singleton hy]
exact nhdsWithin_le_nhds