English
For s ∈ 𝓤 α, there exists t ∈ 𝓤 α such that IsSymmetricRel t and t ∘ t ⊆ s.
Русский
Для s ∈ 𝓤 α существует t ∈ 𝓤 α, такое что t симметрично и t ∘ t ⊆ s.
LaTeX
$$$$\\forall s ∈ 𝓤 α,\\; \\exists t ∈ 𝓤 α:\\ IsSymmetricRel t ∧ t ∘ t ⊆ s.$$$$
Lean4
/-- See also `comp_open_symm_mem_uniformity_sets`. -/
theorem comp_symm_mem_uniformity_sets {s : Set (α × α)} (hs : s ∈ 𝓤 α) : ∃ t ∈ 𝓤 α, IsSymmetricRel t ∧ t ○ t ⊆ s :=
by
obtain ⟨w, w_in, w_sub⟩ : ∃ w ∈ 𝓤 α, w ○ w ⊆ s := comp_mem_uniformity_sets hs
use symmetrizeRel w, symmetrize_mem_uniformity w_in, symmetric_symmetrizeRel w
have : symmetrizeRel w ⊆ w := symmetrizeRel_subset_self w
calc
symmetrizeRel w ○ symmetrizeRel w
_ ⊆ w ○ w := by gcongr
_ ⊆ s := w_sub