English
If s1 ⊆ s2 and the elements in s2\\s1 map to 1 under g, and f agrees with g on s1, then the products over s1 and s2 under f and g are equal.
Русский
Если s1 ⊆ s2 и элементы в s2\\s1 отправляются в 1 под g, а на s1 f и g совпадают, тогда произведения совпадают.
LaTeX
$$$\\prod_{i \\in s_1} f(i) = \\prod_{i \\in s_2} g(i)$ under given conditions$$
Lean4
@[to_additive]
theorem prod_subset_one_on_sdiff [DecidableEq ι] (h : s₁ ⊆ s₂) (hg : ∀ x ∈ s₂ \ s₁, g x = 1)
(hfg : ∀ x ∈ s₁, f x = g x) : ∏ i ∈ s₁, f i = ∏ i ∈ s₂, g i :=
by
rw [← prod_sdiff h, prod_eq_one hg, one_mul]
exact prod_congr rfl hfg