English
If 0 ≤ x < 1, then for all natural n, the sum ∑_{i=m}^{n-1} x^i ≤ x^m/(1 − x).
Русский
Если 0 ≤ x < 1, то для всех натуральных m,n выполняется ∑_{i=m}^{n-1} x^i ≤ x^m/(1 − x).
LaTeX
$$$\\sum_{i=m}^{n-1} x^i \\le \\dfrac{x^m}{1-x}$ при $0\\le x<1$$$
Lean4
theorem geom_sum_Ico_le_of_lt_one (hx : 0 ≤ x) (h'x : x < 1) : ∑ i ∈ Ico m n, x ^ i ≤ x ^ m / (1 - x) :=
by
rcases le_or_gt m n with (hmn | hmn)
· rw [geom_sum_Ico' h'x.ne hmn]
apply div_le_div₀ (pow_nonneg hx _) _ (sub_pos.2 h'x) le_rfl
simpa using pow_nonneg hx _
· rw [Ico_eq_empty, sum_empty]
· apply div_nonneg (pow_nonneg hx _)
simpa using h'x.le
· simpa using hmn.le