English
Subtracting p from the left argument yields the same pattern with +1: toIocDiv hp (a - p) b = toIocDiv hp a b + 1.
Русский
Вычитание p из левого аргумента сохраняет закономерность: toIocDiv hp (a - p) b = toIocDiv hp a b + 1.
LaTeX
$$$\operatorname{toIocDiv}\\_{hp}(a - p, b) = \operatorname{toIocDiv}\\_{hp}(a, b) + 1$$$
Lean4
@[simp]
theorem toIocDiv_sub' (a b : α) : toIocDiv hp (a - p) b = toIocDiv hp a b + 1 := by
simpa only [one_zsmul] using toIocDiv_sub_zsmul' hp a b 1