English
Let S be a domain and T → S an algebra. Then the roots of the polynomial X over S are exactly 0, i.e., X has a single root at 0 with multiplicity 1.
Русский
Пусть S — область, существует алгебраическое отображение T → S. Тогда корни полинома X в S равны {0}.
LaTeX
$$$$ \operatorname{aroots}(X)_S = \{0\} $$$$
Lean4
@[simp]
theorem aroots_X [CommRing S] [IsDomain S] [Algebra T S] : aroots (X : T[X]) S = {0} := by
rw [aroots_def, map_X, roots_X]