English
If inv(a+b) = inv(a) + inv(b), then a * inv(b) * a = b * inv(a) * b.
Русский
Если inv(a+b) = inv(a) + inv(b), то a inv(b) a = b inv(a) b.
LaTeX
$$a * ⅟b * a = b * ⅟a * b$$
Lean4
theorem eq_of_invOf_add_eq_invOf_add_invOf [Ring R] {a b : R} [Invertible a] [Invertible b] [Invertible (a + b)]
(h : ⅟(a + b) = ⅟a + ⅟b) : a * ⅟b * a = b * ⅟a * b :=
by
have h' := neg_one_eq_invOf_mul_add_invOf_mul_iff.mp h
have h_a_binv_a : -(b + a) = a * ⅟b * a := neg_add_eq_mul_invOf_mul_same_iff.mpr h'
have h_b_ainv_b : -(a + b) = b * ⅟a * b := by
rw [add_comm] at h'
exact neg_add_eq_mul_invOf_mul_same_iff.mpr h'
rw [← h_a_binv_a, ← h_b_ainv_b, add_comm]