English
For f: X → Y and s constructible in Y, the preimage f^{-1}(s) is constructible.
Русский
Для f: X → Y и s конструктивна во множестве Y, тогда предобраз f^{-1}(s) конструктивен.
LaTeX
$$$\forall f, \ IsConstructible(s) \Rightarrow \ IsConstructible(f^{-1}(s)).$$$
Lean4
@[stacks 054I]
theorem isConstructible_preimage (f : X.Hom Y) {s : Set Y} (hs : IsConstructible s) : IsConstructible (f.base ⁻¹' s) :=
hs.preimage f.continuous fun t ht ht' ↦
IsRetrocompact_iff_isSpectralMap_subtypeVal.mpr
((quasiCompact_iff_spectral _).mp
(MorphismProperty.of_isPullback (P := @QuasiCompact) (isPullback_morphismRestrict f ⟨t, ht⟩)
((quasiCompact_iff_spectral _).mpr (IsRetrocompact_iff_isSpectralMap_subtypeVal.mp ht'))))