English
If a map f factors through Spec of a quotient by I so that the composition with the quotient map equals the universal sigmaSpec, then I is the zero ideal.
Русский
Если отображение f через спектр фактор-момета по I даёт композицию равную sigmaSpec, то I=0.
LaTeX
$$If f: ∐ Spec(R_i) → Spec(Π R_i / I) satisfies f ≫ Spec.map (Ideal.Quotient.mk I) = sigmaSpec R, then I = ⊥.$$
Lean4
theorem eq_bot_of_comp_quotientMk_eq_sigmaSpec (I : Ideal (Π i, R i))
(f : (∐ fun i ↦ Spec (R i)) ⟶ Spec (.of <| (Π i, R i) ⧸ I))
(hf : f ≫ Spec.map (CommRingCat.ofHom (Ideal.Quotient.mk I)) = sigmaSpec R) : I = ⊥ :=
by
refine le_bot_iff.mp fun x hx ↦ ?_
ext i
simpa [← Category.assoc, Ideal.Quotient.eq_zero_iff_mem.mpr hx] using
congr((Spec.preimage (Sigma.ι (Spec <| R ·) i ≫ $hf)).hom x).symm