English
Cocycle identity involving two snd maps; confirms compatibility of second projections.
Русский
Кокосовое тождество с двумя snd; подтверждает совместимость вторых проекций.
LaTeX
$$$ t'_{\\mathcal{U}} f g i j k \\;\\gg\\; \\mathrm{snd} \\_ \\_ \\;\\gg\\; \\mathrm{snd} \\_ \\_ = \\mathrm{snd} \\_ \\_ \\;\\gg\\; \\mathrm{snd} \\_ \\_ $$
Lean4
theorem cocycle_snd_snd (i j k : 𝒰.I₀) :
t' 𝒰 f g i j k ≫ t' 𝒰 f g j k i ≫ t' 𝒰 f g k i j ≫ pullback.snd _ _ ≫ pullback.snd _ _ =
pullback.snd _ _ ≫ pullback.snd _ _ :=
by
simp only [t'_snd_snd, t'_fst_fst_fst, t'_fst_snd]
-- `by tidy` should solve it, but it times out.