English
If f is analytic within s at x, and g agrees with f on s near x (g =ᶠ[𝓝[s] x] f) and g(x) = f(x), then g is analytic within s at x.
Русский
Если f аналитична внутри s в точке x, и g совпадает с f на окрестности x внутри s (g =ᶠ[𝓝[s] x] f) и g(x) = f(x), тогда g аналитична внутри s в x.
LaTeX
$$$\text{AnalyticWithinAt}_{\mathcal{K}}(f,s,x) \land (g =^\!\!_{\mathcal{N}\!hdsWithin[s] x} f) \land (g(x)=f(x)) \Rightarrow \text{AnalyticWithinAt}_{\mathcal{K}}(g,s,x)$$$
Lean4
theorem congr_of_eventuallyEq {f g : E → F} {s : Set E} {x : E} (hf : AnalyticWithinAt 𝕜 f s x) (hs : g =ᶠ[𝓝[s] x] f)
(hx : g x = f x) : AnalyticWithinAt 𝕜 g s x :=
by
rcases hf with ⟨p, hp⟩
exact ⟨p, hp.congr hs hx⟩