English
For a finite index set ι, expGrowthInf(iInf i => u_i) = iInf i => expGrowthInf(u_i).
Русский
Для конечного индексного множества i: expGrowthInf( iInf i, u(i) ) = iInf i, expGrowthInf(u(i)).
LaTeX
$$$\expGrowthInf\left(\inf_{i} u_i\right) = \inf_{i} \expGrowthInf(u_i)$$$
Lean4
theorem expGrowthInf_biInf {α : Type*} (u : α → ℕ → ℝ≥0∞) {s : Set α} (hs : s.Finite) :
expGrowthInf (⨅ x ∈ s, u x) = ⨅ x ∈ s, expGrowthInf (u x) :=
by
have := map_finset_inf expGrowthInfTopHom hs.toFinset u
simpa only [expGrowthInfTopHom, InfTopHom.coe_mk, InfHom.coe_mk, Finset.inf_eq_iInf, hs.mem_toFinset, comp_apply]