English
Under appropriate hypotheses, linearGrowthSup (u+v) ≤ linearGrowthSup u + linearGrowthSup v.
Русский
При подходящих предпосылках линейный верхний рост суммы не превышает сумму верхних ростов.
LaTeX
$$$\operatorname{linearGrowthSup}(u+v) \le \operatorname{linearGrowthSup}(u) + \operatorname{linearGrowthSup}(v)$$$
Lean4
theorem linearGrowthSup_add_le (h : linearGrowthSup u ≠ ⊥ ∨ linearGrowthSup v ≠ ⊤)
(h' : linearGrowthSup u ≠ ⊤ ∨ linearGrowthSup v ≠ ⊥) :
linearGrowthSup (u + v) ≤ linearGrowthSup u + linearGrowthSup v :=
by
refine (limsup_add_le h h').trans_eq' (limsup_congr (Eventually.of_forall fun n ↦ ?_))
rw [Pi.add_apply, Pi.add_apply, add_div_of_nonneg_right n.cast_nonneg']