English
For any f: M1 → M and p: M → N, the equality N.freeHomEquiv (f ≫ p) i = sectionsMap p (M.freeHomEquiv f i) holds for all i ∈ I.
Русский
Для любых f: M1 → M и p: M → N верно для всех i: N.freeHomEquiv (f ≫ p) i = sectionsMap p (M.freeHomEquiv f i).
LaTeX
$$$N.freeHomEquiv (f \circ p)\, i = \mathrm{sectionsMap}(p, (M.freeHomEquiv\, f)\, i)$$$
Lean4
theorem freeHomEquiv_symm_comp {M N : SheafOfModules.{u} R} {I : Type u} (s : I → M.sections) (p : M ⟶ N) :
M.freeHomEquiv.symm s ≫ p = N.freeHomEquiv.symm (fun i ↦ sectionsMap p (s i)) :=
N.freeHomEquiv.injective (by ext; simp [freeHomEquiv_comp_apply])