English
For any f and x and s, HasDerivWithinAt f f' s x is equivalent to HasFDerivWithinAt f (f' 1) s x.
Русский
Для любой функции f и точек x и множества s, HasDerivWithinAt f f' s x эквивалентно HasFDerivWithinAt f (f' 1) s x.
LaTeX
$$$\\text{HasDerivWithinAt}(f,f',s,x) \\iff \\text{HasFDerivWithinAt}(f,f',s,x).$$$
Lean4
/-- Derivative of `f` at the point `x`, if it exists. Zero otherwise.
If the derivative exists (i.e., `∃ f', HasDerivAt f f' x`), then
`f x' = f x + (x' - x) • deriv f x + o(x' - x)` where `x'` converges to `x`.
-/
def deriv (f : 𝕜 → F) (x : 𝕜) :=
fderiv 𝕜 f x 1