English
If hc is strict derivative of c at x and hu is strict derivative of u at x, then the derivative of y ↦ (c(y))(u(y)) is c'(u(x)) + c(x)(u'(x)).
Русский
Если c имеет строгую производную в x и u имеет строгую производную в x, то производная y ↦ c(y)(u(y)) равна c'(u(x)) + c(x)(u'(x)).
LaTeX
$$$HasStrictDerivAt\\left(c,c',x\\right) \\Rightarrow HasStrictDerivAt\\left( y \\mapsto (c(y))(u(y))\\right)\\left(c'(u(x)) + c(x)u'\\right) x$$$
Lean4
theorem clm_comp (hc : HasDerivAt c c' x) (hd : HasDerivAt d d' x) :
HasDerivAt (fun y => (c y).comp (d y)) (c'.comp (d x) + (c x).comp d') x :=
by
rw [← hasDerivWithinAt_univ] at *
exact hc.clm_comp hd