English
Same as above: iterates preserve differentiability within s with derivatives (f')^n.
Русский
То же самое: итерации сохраняют дифференцируемость внутри s с производными (f')^n.
LaTeX
$$$$ \text{HasFDerivWithinAt } f f' s x \to f x = x \to \forall n,\; \text{HasFDerivWithinAt } f^{[n]} (f')^{n} s x. $$$$
Lean4
@[fun_prop]
protected theorem iterate {f : E → E} {f' : E →L[𝕜] E} (hf : HasFDerivWithinAt f f' s x) (hx : f x = x)
(hs : MapsTo f s s) (n : ℕ) : HasFDerivWithinAt f^[n] (f' ^ n) s x :=
by
refine HasFDerivAtFilter.iterate hf ?_ hx n
rw [nhdsWithin]
convert tendsto_inf.2 ⟨hf.continuousWithinAt, _⟩
exacts [hx.symm, (tendsto_principal_principal.2 hs).mono_left inf_le_right]