English
Same as the conjugation rule for exp(i x): the conjugate of exp(i x) equals exp(-i x).
Русский
То же самое про сопряжение: сопряжение exp(i x) равно exp(-i x).
LaTeX
$$$$ \\overline{\\exp(i x)} = \\exp(- i x). $$$$
Lean4
/-- The additive character from `ℝ` onto the circle, given by `fun x ↦ exp (2 * π * x * I)`.
Denoted as `𝐞` within the `Real.FourierTransform` namespace. This uses the analyst convention that
there is a `2 * π` in the exponent. -/
def fourierChar : AddChar ℝ Circle where
toFun z := .exp (2 * π * z)
map_zero_eq_one' := by rw [mul_zero, Circle.exp_zero]
map_add_eq_mul' x y := by rw [mul_add, Circle.exp_add]