English
The spectral norm is nonarchimedean, i.e., it satisfies the ultrametric inequality: for all x,y in L, spectralNorm(x+y) ≤ max(spectralNorm(x), spectralNorm(y)).
Русский
Спектральная норма удовлетворяет неархимедовуне неравенство: для любых x,y ∈ L выполняется spectralNorm(x+y) ≤ max(spectralNorm(x), spectralNorm(y)).
LaTeX
$$$\forall x,y \in L, \; \operatorname{spectralNorm}_{K,L}(x+y) \le \max\big(\operatorname{spectralNorm}_{K,L}(x), \operatorname{spectralNorm}_{K,L}(y)\big)$$$
Lean4
/-- The spectral norm is nonarchimedean when `L/K` is finite and normal.
See also `isNonarchimedean_spectralNorm` for a more general result. -/
theorem isNonarchimedean_spectralNorm_of_finiteDimensional_normal [IsUltrametricDist K] :
IsNonarchimedean (spectralNorm K L) :=
by
rw [spectralNorm_eq_invariantExtension]
exact isNonarchimedean_invariantExtension K L