English
The functoriality of mapL with respect to composition: mapL (i ↦ g_i ∘ f_i) = mapL g ∘ mapL f.
Русский
Функториальность mapL по отношению к композиции: mapL (i ↦ g_i ∘ f_i) = mapL g ∘ mapL f.
LaTeX
$$$ \\mathrm{mapL}(\\lambda i, g_i \\circ f_i) = (\\mathrm{mapL}\\, g) \\circ (\\mathrm{mapL}\\, f) $$$
Lean4
theorem mapL_comp : mapL (fun (i : ι) ↦ g i ∘L f i) = mapL g ∘L mapL f :=
by
apply ContinuousLinearMap.coe_injective
ext
simp only [mapL_coe, ContinuousLinearMap.coe_comp, LinearMap.compMultilinearMap_apply, map_tprod, LinearMap.coe_comp,
ContinuousLinearMap.coe_coe, Function.comp_apply]