English
If Re(z) < 0 and Im(z) = 0, then log z has a limit as one approaches z from the lower half-plane, namely log|z| − π i.
Русский
Если Re(z) < 0 и Im(z) = 0, то логарифм z имеет предел при подходе снизу к z: log|z| − π i.
LaTeX
$$$\text{If } \mathrm{Re}(z) < 0 \text{ and } \mathrm{Im}(z) = 0,\quad \mathrm{Tendsto}\log(\mathcal{N}_{z}^{\{w: w.im<0\}}) \to \log \lVert z \rVert - \pi i$$$
Lean4
theorem tendsto_log_nhdsWithin_im_neg_of_re_neg_of_im_zero {z : ℂ} (hre : z.re < 0) (him : z.im = 0) :
Tendsto log (𝓝[{z : ℂ | z.im < 0}] z) (𝓝 <| Real.log ‖z‖ - π * I) :=
by
convert
(continuous_ofReal.continuousAt.comp_continuousWithinAt (continuous_norm.continuousWithinAt.log _)).tendsto.add
(((continuous_ofReal.tendsto _).comp <| tendsto_arg_nhdsWithin_im_neg_of_re_neg_of_im_zero hre him).mul
tendsto_const_nhds) using
1
· simp [sub_eq_add_neg]
· lift z to ℝ using him
simpa using hre.ne